3.2.40 \(\int \frac {(b x^n)^{3/2}}{x^2} \, dx\) [140]

Optimal. Leaf size=24 \[ -\frac {2 b x^{-1+n} \sqrt {b x^n}}{2-3 n} \]

[Out]

-2*b*x^(-1+n)*(b*x^n)^(1/2)/(2-3*n)

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Rubi [A]
time = 0.01, antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {15, 30} \begin {gather*} -\frac {2 b x^{n-1} \sqrt {b x^n}}{2-3 n} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(b*x^n)^(3/2)/x^2,x]

[Out]

(-2*b*x^(-1 + n)*Sqrt[b*x^n])/(2 - 3*n)

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[a^IntPart[m]*((a*x^n)^FracPart[m]/x^(n*FracPart[m])), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {\left (b x^n\right )^{3/2}}{x^2} \, dx &=\left (b x^{-n/2} \sqrt {b x^n}\right ) \int x^{-2+\frac {3 n}{2}} \, dx\\ &=-\frac {2 b x^{-1+n} \sqrt {b x^n}}{2-3 n}\\ \end {align*}

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Mathematica [A]
time = 0.00, size = 22, normalized size = 0.92 \begin {gather*} \frac {\left (b x^n\right )^{3/2}}{\left (-1+\frac {3 n}{2}\right ) x} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(b*x^n)^(3/2)/x^2,x]

[Out]

(b*x^n)^(3/2)/((-1 + (3*n)/2)*x)

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Maple [A]
time = 0.02, size = 20, normalized size = 0.83

method	result	size
gosper	\(\frac {2 \left (b \,x^{n}\right )^{\frac {3}{2}}}{x \left (-2+3 n \right )}\)	\(20\)
risch	\(\frac {2 b^{2} x^{2 n}}{\left (-2+3 n \right ) x \sqrt {b \,x^{n}}}\)	\(28\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^n)^(3/2)/x^2,x,method=_RETURNVERBOSE)

[Out]

2/x/(-2+3*n)*(b*x^n)^(3/2)

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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^n)^(3/2)/x^2,x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume((3*n)/2-2>0)', see `assume?` f
or more deta

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Fricas [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^n)^(3/2)/x^2,x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (ha
s polynomial part)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \begin {cases} \frac {2 \left (b x^{n}\right )^{\frac {3}{2}}}{3 n x - 2 x} & \text {for}\: n \neq \frac {2}{3} \\\int \frac {\left (b x^{\frac {2}{3}}\right )^{\frac {3}{2}}}{x^{2}}\, dx & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**n)**(3/2)/x**2,x)

[Out]

Piecewise((2*(b*x**n)**(3/2)/(3*n*x - 2*x), Ne(n, 2/3)), (Integral((b*x**(2/3))**(3/2)/x**2, x), True))

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^n)^(3/2)/x^2,x, algorithm="giac")

[Out]

integrate((b*x^n)^(3/2)/x^2, x)

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Mupad [B]
time = 0.93, size = 22, normalized size = 0.92 \begin {gather*} \frac {2\,b\,x^{n-1}\,\sqrt {b\,x^n}}{3\,n-2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^n)^(3/2)/x^2,x)

[Out]

(2*b*x^(n - 1)*(b*x^n)^(1/2))/(3*n - 2)

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